Become Ruby Association Certified with updated Ruby-Programmer-Gold exam questions and correct answers
Review the following Ruby code snippet:def divide_numbers(x, y) x / yrescue ZeroDivisionError => e puts "Error: #{e.message}"end result1 = divide_numbers(10, 2)result2 = divide_numbers(10, 0)result3 = begin divide_numbers(10, '5') rescue TypeError => e "Caught: #{e.class}" endresult4 = divide_numbers(10, nil) rescue "Invalid operation" What will be the values of result1, result2, result3, and result4, respectively?
In Ruby, the understanding of operators and their precedence is crucial for writing correct and efficient code. Consider the following Ruby code snippet:a = 10b = 3result1 = a + b * 2result2 = (a + b) % 3result3 = a ** b / 2 Based on this code, which two of the following statements are true regarding the use of operators and their precedence?
In Ruby, the understanding of operators and their precedence is crucial for writing correct and efficient code. Consider the following Ruby code snippet:a = 10b = 3result1 = a + b * 2result2 = (a + b) % 3result3 = a ** b / 2 Based on this code, which two of the following statements are true regarding the use of operators and their precedence?
Analyze the following Ruby code snippet in the context of class design and instance variable management:class Book attr_reader :title, :author @@total_books = 0 def self.total_books @@total_books end def initialize(title, author) @title = title @author = author @@total_books += 1 endendclass Library attr_reader :books def initialize @books = [] end def add_book(book) @books
Review the following Ruby code snippet in the context of class inheritance and method access control:class Product def initialize(name, price) @name = name @price = price end private def price @price endendclass Electronic < Product def discount_amount(discount_percentage) price * discount_percentage / 100.0 end def discounted_price(discount_percentage) price - discount_amount(discount_percentage) endendelectronic_item = Electronic.new("Laptop", 1000)result = electronic_item.discounted_price(20)What will be the value of result?
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