Free Ruby Association Ruby-Programmer-Gold Exam Questions

Question 1

In Ruby, the understanding of operators and their precedence is crucial for writing correct and efficient code. Consider the following Ruby code snippet:a = 10b = 3result1 = a + b * 2result2 = (a + b) % 3result3 = a ** b / 2 Based on this code, which two of the following statements are true regarding the use of operators and their precedence?

A : result2 calculates the remainder of a + b divided by 3 due to the % operator.

B : result2 equals 1 because parentheses change the order of operations, prioritizing addition over modulo.

C : result1 equals 16 because addition (+) has a higher precedence than multiplication (*).

D : result3 results in 50 because division (/) has a higher precedence than exponentiation (**).

E : In result1, the multiplication (*) is performed before addition (+) due to operator precedence.

Answer: A,E

Question 2

Review the following Ruby code snippet in the context of class inheritance and method access control:class Product def initialize(name, price) @name = name @price = price end private def price @price endendclass Electronic < Product def discount_amount(discount_percentage) price * discount_percentage / 100.0 end def discounted_price(discount_percentage) price - discount_amount(discount_percentage) endendelectronic_item = Electronic.new("Laptop", 1000)result = electronic_item.discounted_price(20)What will be the value of result?

A : 800

B : NoMethodError

C : 200

D : 1000

Answer: B

Question 3

In Ruby, the understanding of operators and their precedence is crucial for writing correct and efficient code. Consider the following Ruby code snippet:a = 10b = 3result1 = a + b * 2result2 = (a + b) % 3result3 = a ** b / 2 Based on this code, which two of the following statements are true regarding the use of operators and their precedence?

A : result2 calculates the remainder of a + b divided by 3 due to the % operator.

B : result2 equals 1 because parentheses change the order of operations, prioritizing addition over modulo.

C : result1 equals 16 because addition (+) has a higher precedence than multiplication (*).

D : result3 results in 50 because division (/) has a higher precedence than exponentiation (**).

E : In result1, the multiplication (*) is performed before addition (+) due to operator precedence.

Answer: A,E

Question 4

In Ruby, understanding non-local exits such as break, next, and return within the context of blocks and methods is crucial for controlling the flow of a program. Consider the following Ruby code snippet:def test_method [1, 2, 3].each do |i| return i if i == 2 end "No match"end result = test_method Based on this code, which two of the following statements are true regarding non-local exits in Ruby?

A : The return keyword in the block causes an exit from the each loop and returns 2 from the test_method.

B : The return keyword in the block causes the entire program to exit, assigning nil to result.

C : The result variable will be assigned the string "No match" because the each loop completes its iteration.

D : If i equals 2, the each loop is exited and the test_method returns "No match".

E : The return keyword inside the block exits the block and continues execution with the next line after the each loop.

Answer: A,E

Question 5

Examine the following Ruby code snippet:a = 2b = 3c = '4'result1 = a * bresult2 = a * cresult3 = c * bresult4 = c + a

A : 6, TypeError, '444', TypeError

B : 6, '24', '444', TypeError

C : 6, '6', '444', TypeError

D : 6, TypeError, TypeError, TypeError

Answer: B