Become Ruby Association Certified with updated Ruby-Programmer-Gold exam questions and correct answers
In Ruby, understanding non-local exits such as break, next, and return within the context of blocks and methods is crucial for controlling the flow of a program. Consider the following Ruby code snippet:def test_method [1, 2, 3].each do |i| return i if i == 2 end "No match"end result = test_method Based on this code, which two of the following statements are true regarding non-local exits in Ruby?
Consider the following Ruby code snippet involving the implementation and usage of the Comparable module:class TimeRange include Comparable attr_reader :start_time, :end_time def initialize(start_time, end_time) @start_time = start_time @end_time = end_time end def (other) return nil unless other.is_a?(TimeRange) [start_time, end_time] [other.start_time, other.end_time] endend time_range1 = TimeRange.new(10, 20)time_range2 = TimeRange.new(15, 25)time_range3 = TimeRange.new(10, 20) result1 = time_range1 time_range3 What will be the values of result1, result2, and result3, respectively?
Analyze the following Ruby code snippet that utilizes regular expressions for string processing:class EmailExtractor EMAIL_REGEX = /(\b[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Z|a-z]{2,}\b)/ def self.extract_from(text) text.scan(EMAIL_REGEX).flatten endend text1 = "Contact us at support@example.com for assistance"text2 = "Send your feedback to: feedback@example.co.uk and admin@example.com"text3 = "No emails here!" result1 = EmailExtractor.extract_from(text1)result2 = EmailExtractor.extract_from(text2)result3 = EmailExtractor.extract_from(text3) What will be the values of result1, result2, and result3, respectively?
Review the following Ruby code snippet in the context of class inheritance and method access control:class Product def initialize(name, price) @name = name @price = price end private def price @price endendclass Electronic < Product def discount_amount(discount_percentage) price * discount_percentage / 100.0 end def discounted_price(discount_percentage) price - discount_amount(discount_percentage) endendelectronic_item = Electronic.new("Laptop", 1000)result = electronic_item.discounted_price(20)What will be the value of result?
Review the following Ruby code snippet:def divide_numbers(x, y) x / yrescue ZeroDivisionError => e puts "Error: #{e.message}"end result1 = divide_numbers(10, 2)result2 = divide_numbers(10, 0)result3 = begin divide_numbers(10, '5') rescue TypeError => e "Caught: #{e.class}" endresult4 = divide_numbers(10, nil) rescue "Invalid operation" What will be the values of result1, result2, result3, and result4, respectively?
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